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Editorial Team
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Asked: 2026-05-27T12:08:03+00:00

I have the following query: SELECT `snap`.`ID`, `user`.`username`, `vote`.`type` FROM (`snap`) JOIN `user` as

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I have the following query:

SELECT `snap`.`ID`, `user`.`username`, `vote`.`type` 
FROM (`snap`) JOIN `user` as u ON `u`.`ID` = `snap`.`user` 
LEFT JOIN (select * from vote where user = "18") as vote ON `snap`.`ID` = `vote`.`snap` 
JOIN (SELECT CEIL(MAX(ID)*RAND()) AS ID FROM snap)) AS x ON `snap`.`ID` => `x`.`ID` 
WHERE `snap`.`active` = 0 LIMIT 1

It worked just fine untill I added the last JOIN. Now i get the error: “Every derived table must have its own alias”. I know it is because every table needs its on alias and I need to put “as S” or something somewhere, but I can’t find out how to do that in this query.

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1 Answer

  1. Editorial Team

    Seems like you have extra closing parenthesis after snap. It should be 1 instead of 2 closing parentheses.

    SELECT `snap`.`ID`, `user`.`username`, `vote`.`type` 
FROM (`snap`) JOIN `user` as u ON `u`.`ID` = `snap`.`user` 
LEFT JOIN (select * from vote where user = "18") as vote ON `snap`.`ID` = `vote`.`snap` 
JOIN (SELECT CEIL(MAX(ID)*RAND()) AS ID FROM snap) AS x ON `snap`.`ID` = `x`.`ID` 
WHERE `snap`.`active` = 0 LIMIT 1
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