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Home/ Questions/Q 8789591
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T22:27:03+00:00 2026-06-13T22:27:03+00:00

I have the following query: SELECT stat.mcq_id, ROUND( stat.total_score / stat.num_taken, 2 ) AS

  • 0

I have the following query:

SELECT 
  stat.mcq_id, 
  ROUND( stat.total_score / stat.num_taken, 2 ) AS avg_score
    FROM (
      SELECT 
        user_mcq.mcq_id, 
        SUM( score ) AS total_score, 
        COUNT( user_mcq.id ) AS num_taken
      FROM user_mcq
      INNER JOIN user ON ( user.id = user_mcq.user_id ) 
      WHERE user.level_id =3
      AND user_mcq.is_complete =1
      GROUP BY user_mcq.mcq_id
    ) AS stat

This produces:

mcq_id  avg_score
1       5.75
2       9.22
6       8.81
7       8.94
14      7.00
16      9.46

I would like to use this to update another table called mcq using mcq_id from the result to match against mcq.id

I’ve tried the following, but without success:

UPDATE mcq SET mcq.avg_score = stats.avg_score FROM (
  SELECT 
  stat.mcq_id, 
  ROUND( stat.total_score / stat.num_taken, 2 ) AS avg_score
    FROM (
      SELECT 
        user_mcq.mcq_id, 
        SUM( score ) AS total_score, 
        COUNT( user_mcq.id ) AS num_taken
      FROM user_mcq
      INNER JOIN user ON ( user.id = user_mcq.user_id ) 
      WHERE user.level_id =3
      AND user_mcq.is_complete =1
      GROUP BY user_mcq.mcq_id
    ) AS stat
) AS stats
WHERE mcq.id = stats.mcq_id;

This gives:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM ( SELECT stat.mcq_id, ROUND( stat.total_score / stat.num_taken, 2 ) A' at line 1
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T22:27:05+00:00Added an answer on June 13, 2026 at 10:27 pm

    I think you can use the join with the able table and update the column as below:

     UPDATE mcq, 
            (SELECT 
                stat.mcq_id, 
                ROUND( stat.total_score / stat.num_taken, 2 ) AS avg_score
                 FROM (SELECT 
                      user_mcq.mcq_id, 
                      SUM(score ) AS total_score, 
                      COUNT( user_mcq.id ) AS num_taken
                      FROM user_mcq
                      INNER JOIN user ON ( user.id = user_mcq.user_id ) 
                      WHERE user.level_id =3
                      AND user_mcq.is_complete =1
                      GROUP BY user_mcq.mcq_id
                 ) AS stat
           ) AS stats
    SET mcq.avg_score = stats.avg_score 
    WHERE mcq.mcq_id = stats.mcq_id;
    
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