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Home/ Questions/Q 6968813
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T16:30:03+00:00 2026-05-27T16:30:03+00:00

I have the following query: $sqltext = SELECT Score FROM HighScore . WHERE fbID=’$_POST[fbID]’

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I have the following query:

$sqltext = "SELECT Score FROM HighScore ".
    "WHERE fbID='$_POST[fbID]' AND ".
        "Layout='$_POST[Layout]'";
$result = mysql_query($sqltext); 

if(mysql_num_rows($result)>0){
    $sql = "UPDATE HighScore SET Score = '$_POST[Score]', ".
        "Time = '$_POST[Time]', ".
        "Stars = '$_POST[Stars]' ".
        "WHERE fbID = '$_POST[fbID]' AND Layout = '$_POST[Layout]'"; 
} else {
    $sql = "INSERT INTO HighScore (fbID, Layout, Score, Time, Stars) ".
        "VALUES ('$_POST[fbID]','$_POST[Layout]',".
        "'$_POST[Score]','$_POST[Time]','$_POST[Stars]')";
}

What does it do? Well it checks if a row is in the database or not (there is always just 1 row or none). If there is no row, it inserts a new one in the database. If the row is present it will update the row. This all works OK.

$sqltext will give a value. This value can be 234, 3424342 or even -392. If this value is smaller than the ‘$_POST[Score]’ value, it should update the row. Currently it doesn’t and I can’t seem to get this working properly. So how can I make it so, that if $sqltext (which is Score from the db) < ‘$_POST[Score]’ it should update the row and else ignore it? (also not insert).

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T16:30:03+00:00Added an answer on May 27, 2026 at 4:30 pm
    $sqltext= "SELECT Score FROM HighScore WHERE fbID='$_POST[fbID]'AND Layout='$_POST[Layout]'"; $result = mysql_query($sqltext); 
    
    if(mysql_num_rows($result)>0){
      if ($row = mysql_fetch_assoc($result))
      {
        if ($row['Score'] < $_POST['Score'])
        {
                $sql="UPDATE HighScore SET Score = '$_POST[Score]', Time = '$_POST[Time]', Stars = '$_POST[Stars]' WHERE fbID = '$_POST[fbID]' AND Layout = '$_POST[Layout]'"; 
        }
      }
    }else{
                $sql="INSERT INTO HighScore (fbID, Layout, Score, Time, Stars) VALUES ('$_POST[fbID]','$_POST[Layout]','$_POST[Score]','$_POST[Time]','$_POST[Stars]')";
    }
    

    I think this is what you want. But it does not do anything, if there is a row AND the score is higher than the Score in POST[‘Score’]

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