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Home/ Questions/Q 8610505
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T04:08:48+00:00 2026-06-12T04:08:48+00:00

I have the following query: titles = Title.objects.all() I need to get DISTINCT (‘title’)

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I have the following query:

titles = Title.objects.all()

I need to get DISTINCT ('title') for this query under certain circumstances. Django does not allow distinct('title') while using a MySQL backend.

Essentially, what I want to do is something like:

titles = titles.extra('GROUP BY title')

How would I do this correctly?

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  1. Editorial Team
    Editorial Team
    2026-06-12T04:08:49+00:00Added an answer on June 12, 2026 at 4:08 am

    You need to do [annotate][1] to group by

    titles = titles.annotate(Count("title")).order_by()
    
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