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Home/ Questions/Q 8868285
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T17:14:09+00:00 2026-06-14T17:14:09+00:00

I have the following query, which generally works, and is supposed to return all

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I have the following query, which generally works, and is supposed to return all rows covering the define timeframe (taking the closest prior and next rows if no absolut match – outlined at http://www.orafaq.com/node/1834)

SELECT * FROM table
  WHERE id=__ID__ AND `date` BETWEEN 
    IFNULL((SELECT MAX(`date`) FROM table WHERE id=__ID__ AND `date`<=__LOWERLIMIT__), 0)
  AND
    IFNULL((SELECT MIN(`date`) FROM table WHERE id=__ID__ AND `date`>=__UPPERLIMIT__), UNIX_TIMESTAMP())
ORDER BY `date`

but was hoping to reduce the two table subselects by referencing to the outer select, but obviously it doesnt like it

SELECT * FROM (SELECT * FROM table WHERE id=__ID__) b
  WHERE `date` BETWEEN 
    IFNULL((SELECT MAX(`date`) FROM b WHERE `date`<=__LOWERLIMIT__), 0)
  AND
    IFNULL((SELECT MIN(`date`) FROM b WHERE `date`>=__UPPERLIMIT__), UNIX_TIMESTAMP())
ORDER BY `date`

Is there a way to have the query without the three table selects?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T17:14:10+00:00Added an answer on June 14, 2026 at 5:14 pm

    You can do something like this with a join:

    select * from table a
        inner join (
           select id,
                  max(
                      if(`date` <= __LOWERLIMIT__ ,`date`, 0)
                  ) as min_date,              
                  min(
                     if(`date` >= __UPPERLIMIT__ , `date`, UNIX_TIMESTAMP())
                  ) as max_date
               from table
               where id = __ID__
               group by id
        ) range on
        range.id = a.id and
        a.`date` between min_date and max_date;
    

    I’m not a MySQL expert, so apologies if a bit of syntax tweaking is needed.

    Update: the OP also found this very nice solution.

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