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Home/ Questions/Q 9014585
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T03:32:42+00:00 2026-06-16T03:32:42+00:00

I have the following regexp: pattern = re.compile(rHESAID:|SHESAID:) It’s working correctly. I use it

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I have the following regexp:

pattern = re.compile(r"HESAID:|SHESAID:")

It’s working correctly. I use it to split by multiple delimiters like this:

result = pattern.split(content)

What I want to add is verification so that the split does NOT happend unless HESAID: or SHESAID: are placed on new lines. This is not working:

pattern = re.compile(r"\nHESAID:\n|\nSHESAID:\n")

Please help.

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  1. Editorial Team
    Editorial Team
    2026-06-16T03:32:43+00:00Added an answer on June 16, 2026 at 3:32 am

    It would be helpful if you elaborated on how exactly it is not working, but I am guessing that the issue is that it does not match consecutive lines of HESAID/SHESAID. You can fix this by using beginning and end of line anchors instead of actually putting \n in your regex:

    pattern = re.compile(r'^HESAID:$|^SHESAID:$', re.MULTILINE)
    

    The re.MULTILINE flag is necessary so that ^ and $ match at beginning and end of lines, instead of just the beginning and end of the string.

    I would probably rewrite the regex as follows, the ? after the S makes it optional:

    pattern = re.compile(r'^S?HESAID:$', re.MULTILINE)
    
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