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Home/ Questions/Q 6350163
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T21:45:37+00:00 2026-05-24T21:45:37+00:00

I have the following regular expression in javascript : var the_regexp = /^\/([!\/]*)\/?(\w*)\??([\=|\w]*)\/?$/gi It

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I have the following regular expression in javascript :

var the_regexp = /^\/([!\/]*)\/?(\w*)\??([\=|\w]*)\/?$/gi

It Firefox and Chrome console, it find a match for the string “/d” once every two attemps.

>the_regexp
/^\/([!\/]*)\/?(\w*)\??([\=|\w]*)\/?$/gi
>the_regexp.exec("/d")
null
>the_regexp.exec("/d")
["/d", "", "d", ""]
>the_regexp.exec("/d")
null
>the_regexp.exec("/d")
["/d", "", "d", ""]

Can somebody explain this behaviour ?

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  1. Editorial Team
    Editorial Team
    2026-05-24T21:45:37+00:00Added an answer on May 24, 2026 at 9:45 pm

    MDN Docs:

    If your regular expression uses the “g” flag, you can use the exec
    method multiple times to find successive matches in the same string.
    When you do so, the search starts at the substring of str specified by
    the regular expression’s lastIndex property

    So when your regex has a g flag, and you use the exec method once, the next time you execute it it will search for a match after the first match. In this case, there is none: exec will return null and the lastIndex property will be reset.

    For example:

    var str = "abcdef";
    //         ^ starting index for search is here
    var regex = /ab/g;
    
    regex.exec(str);
    // str: "abcdef"
    //         ^ starting index for search is now here
    
    regex.exec(str);
    // no match found from starting index, return null and reset
    // str: "abcdef"
    //       ^ starting index reset
    

    I’m sorry for my bad wordings etc, I’m not fully awake…

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