Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7871037
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 3, 20262026-06-03T01:47:32+00:00 2026-06-03T01:47:32+00:00

I have the following regular expression which specifies characters the user is allowed to

  • 0

I have the following regular expression which specifies characters the user is allowed to type:

@"^[A-Za-z0-9/!\$%\^&\*\(\)\-_\+\[\]\{\}\;\:\'\£\@\#\.\?]*$

I know ‘\s‘ is the character class for white space, but how do I add this to the regular expression so it excludes it? I have searched for this on Stack Overflow – the questions provide solutions to exclude white space but not how to use it in an existing regular expression. If I add it like I have the other characters, it would mean ‘allow white space’?

Edit: Not sure why this has been marked down? Thanks to everyone for their answers

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-03T01:47:33+00:00Added an answer on June 3, 2026 at 1:47 am

    First of all, you don’t need all those escapes.
    Second of all, the regex already doesn’t allow whitespaces.

    @"^[A-Za-z0-9\[\]/!$%^&*()\-_+{};:'£@#.?]*$"
    

    The [] define a set of characters to allow (followed by * means that characters from the characters set can be zero or more times).

    ^ matches the beginning and $ matches the end, so the fact that /s isn’t anywhere there, means white spaces won’t be allowed.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have the following regular expression, which I think should match any character that
I have the following regular expression which is used to give me the tags
I have the following Regular Expression which matches an email address format: ^[\w\.\-]+@([\w\-]+\.)+[a-zA-Z]+$ This
I have written following regular expression /^[A-Za-z0-9-_\s]*$/ in PHP which allows numbers, letters, spaces,
I have the following regular expression which validates the British National Insurance Number ^([a-zA-Z]){2}(
I have the following regular expression in JavaScript which matches strings like 12:23:34:45 and
I have the following regular expression, which lets me parse percentages like '20%+', '20%',
I have the following regular expression: [0-9]{8}.*\n.*\n.*\n.*\n.* Which I have tested in Expresso against
I have the following regular expression in a validation rule: ^[a-zA-Z0-9',!;?~>+&\\-@#%*.\s]{1,1000}$ However, I can
I have the following regular expression that works fine in perl: Classification:\s([^\n]+?)(?:\sRange:\s([^\n]+?))*(?:\sStructural Integrity:\s([^\n]+))*\n The

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.