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Home/ Questions/Q 609419
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T17:33:54+00:00 2026-05-13T17:33:54+00:00

I have the following replace function myString.replace(/\s\w(?=\s)/,$1\xA0); The aim is to take single-letter words

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I have the following replace function

myString.replace(/\s\w(?=\s)/,"$1\xA0");

The aim is to take single-letter words (e.g. prepositions) and add a non-breaking space after them, instead of standard space.

However the above $1 variable doesn’t work for me. It inserts text “$1 ” instead of a part of original matched string + nbsp.

What is the reason for the observed behaviour? Is there any other way to achieve it?

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  1. Editorial Team
    Editorial Team
    2026-05-13T17:33:54+00:00Added an answer on May 13, 2026 at 5:33 pm

    $1 doesn’t work because you don’t have any capturing subgroups.

    The regular expression should be something like /\b(\w+)\s+/.

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