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Home/ Questions/Q 8121965
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T05:40:44+00:00 2026-06-06T05:40:44+00:00

I have the following scenario :- template <typename T> class Base { public: virtual

  • 0

I have the following scenario :-

template <typename T>
class Base {
  public:
    virtual void someFunc() {}
};

class Derived : public Base<int>,
                public Base<float> {
  public:
    virtual void someFunc() { 
      // do something different if Base<int> than if Base<float>
    }
};

Derived *d = new D();
Base<int>* b1 = (Base<int>*) d;
Base<float>* b2 = (Base<float>*) d;

b1->someFunc();
b2->someFunc();

I want to be able to distinguish between these two function calls. Or in other words, over-ride the two base functions with different function bodies.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T05:40:47+00:00Added an answer on June 6, 2026 at 5:40 am

    You could use a shim (this works for any instance of name collisions between base classes, whether template-related or not):

    template <typename T>
    class Base
    {
      public:
        virtual void someFunc() {}
    };
    
    class IntShim : public Base<int>
    {
      protected:
        virtual void someFuncViaInt() = 0;
      public:
        virtual void someFunc() { return someFuncViaInt(); }
    };
    
    class FloatShim : public Base<float>
    {
      protected:
        virtual void someFuncViaFloat() = 0;
      public:
        virtual void someFunc() { return someFuncViaFloat(); }
    };
    
    class Derived : public IntShim, public FloatShim
    {
      protected:
        virtual void someFuncViaInt()
        { 
          // do something for Base<int>
        }
        virtual void someFuncViaFloat()
        { 
          // do something for Base<float>
        }
    };
    
    Derived *d = new D();
    Base<int>* b1 = (Base<int>*) d;
    Base<float>* b2 = (Base<float>*) d;
    
    b1->someFunc();
    b2->someFunc();
    
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