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Home/ Questions/Q 6159741
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T21:10:58+00:00 2026-05-23T21:10:58+00:00

I have the following scenario where both testOne() and testTwo calls same callMe() method.

  • 0

I have the following scenario where
both testOne() and testTwo calls same callMe() method.

How do I decide inside callMe() method who called callMe().

public void testOne(){
    callMe();
}

public void testTwo(){
    callMe();
}

public void callMe(){
    System.out.println("I was called by following method."+methodName);     

}


Any sort of help is appreciated.
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  1. Editorial Team
    Editorial Team
    2026-05-23T21:10:58+00:00Added an answer on May 23, 2026 at 9:10 pm

    Any solution that has you generating a stacktrace and looking at the second frame is one that is going to lead to pain – what you are essentially doing is bypassing the idea of passing what a function needs to it in order for the function to do it’s work.

    If you need the name of the caller method, then just pass it as a parameter. If you need some other piece of data to decide what to do in the callMe() method, pass it (as a boolean, int, etc.).

    It will confuse other developers working on your code why callMe() has what are essentially secret parameters.

    public void testOne(){
        callMe("testOne");
    }
    
    public void testTwo(){
        callMe("testTwo");
    }
    
    public void callMe(String methodName){
        System.out.println("I was called by following method."+methodName);     
    }
    
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