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Home/ Questions/Q 4381026
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T12:35:59+00:00 2026-05-21T12:35:59+00:00

I have the following script: $(#border-radius).click(function(){ var value = $(#border-radius).attr(value); $(div.editable).click(function () { mySQLinsert(value,

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I have the following script:

$("#border-radius").click(function(){   
var value = $("#border-radius").attr("value");
    $("div.editable").click(function () { 
    mySQLinsert(value, '2', this.id)
     $(this).css({
    "-webkit-border-radius": value
    });  
});                      

});

Basically, the “#border-radius” ID is to a text input. You type in a value, click the textbox (can’t figure out a way around this) and then click the div with the class “editable” and it will apply the style “-webkit-border-radius” (I know its not cross-browser), to that DIV.

The mySQLinsert function uses Ajax to send the value of the mySQLinsert function to a mySQL database using a php page (nothing fancy).

Issue: When I click the child div (div inside of a div) it also applies this value to the parent object, and runs the mySQLinsert function and stored it in the database

I need to be able to select both the parent, and the child individually depending on which one is clicked.

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  1. Editorial Team
    Editorial Team
    2026-05-21T12:36:00+00:00Added an answer on May 21, 2026 at 12:36 pm

    You can use stopPropagation() to prevent the click bubbling up to its parent element.

    $("#border-radius").click(function(){   
        var value = $("#border-radius").attr("value");
        $("div.editable").click(function (e) { 
    
           // Note the parameter e passed in the function above
           e.stopPropagation();
    
           mySQLinsert(value, '2', this.id)
           $(this).css({"-webkit-border-radius": value});  
        });                      
    });
    
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