Question

I have the following script:

i=1;
while [ $i -lt 51 ]
do
osascript -e 'tell app "Terminal"
do script "php $i.php"
end tell' &
i=$[$i+1]
done

I am trying to open a terminal window that executes 1 of 50 php scripts. However, I cannot get the value of $1 to print correctly. In fact, In each terminal its just blank. Each scripted is named 1.php to 50.php – how do I get the value of i to print properly to render the correct file name?

Note, I have been applescripting about an hour. Very open to suggestions to a better script. What I am trying to do is run 50 simultaneous PHP scripts in 50 separate windows simultaneously. Thanks!

Answer 1

It’s just a quoting problem – change:

osascript -e 'tell app "Terminal"
do script "php $i.php"
end tell'

to:

osascript -e "tell app \"Terminal\"
do script \"php $i.php\"
end tell"