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Home/ Questions/Q 923133
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T19:08:44+00:00 2026-05-15T19:08:44+00:00

I have the following : <script> $().ready(function() { $(#myVal#).blur(function() { var arr = jQuery.makeArray(

  • 0

I have the following :

<script>
$().ready(function() {

 $("#myVal#").blur(function() {
   var arr = jQuery.makeArray(  $("#myArr").val() )
if ( $("#myVal").val().indexOf(arr) == -1 || $("#myVal").val().indexOf(arr) ==0) {
    arr.push($("#myVal").val());
}
$("#myArr").val(arr)
});
});
</script>
<form action="" method="post" name="myF" id="myF">
 <input type="text" name="myVal" id="myVal" value="">
 <input type="text" name="myArr" id="myArr" value="">
 <br/>
<input type="submit" name="submit" id="submit" value="go">
</form>

I am trying to check and see if a particular value entered to myVal is already in myArr. If so, don’t add to the array. If not, then add to the array. However, the array keeps growing with duplicate values.

what am i doing wrong?

thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-15T19:08:45+00:00Added an answer on May 15, 2026 at 7:08 pm

    First, makeArray is meant to take array-like objects as input, not strings. And I don’t see the purpose here. If you have an actual array arr (perhaps made using split), you can do:

    if ( $.inArray($("#myVal").val(), arr) == -1)
    

    Your current code calls String.indexOf(arr), so arr is implicitly converted to a (comma-separated)string. Then you search for the array string in the new value. This is clearly not what you want.

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