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Home/ Questions/Q 8389893
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T18:50:45+00:00 2026-06-09T18:50:45+00:00

I have the following select dropdown that occurs when a user clicks an item:

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I have the following select dropdown that occurs when a user clicks an item:

        $(this).html($("<select/>", {
          class: 'sel',
        }).append($("<option/>", { text: "WIP" }))
          .append($("<option/>", { text: "C" }))
          .append($("<option/>", { text: "A" }))
          .append($("<option/>", { text: "AR" }))
          .append($("<option/>", { text: "NS" }))
        );

In addition, I have a variable called status that is defined that as either “WIP”, “C”, “A”, “AR”, or “NS”.

status = trim(($(this).text()));

I want to make it such that when I click the select dropdown, the option == status will be selected. For example:

status = "WIP"
<select class="sel">
     <option selected="selected">WIP</option>
     <option>C</option>
     ...
</select>        
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T18:50:47+00:00Added an answer on June 9, 2026 at 6:50 pm

    The way I understand the question, you want to set a default option so that before the user clicks there’ll be an option selected.

    Here’s how you would do that:

    var status = "WIP";
    
    $("<select/>", {
        class: 'sel',
    })
    .append( $("<option/>", { text: "WIP" }) )
    .append( $("<option/>", { text: "C" }) )
    .append( $("<option/>", { text: "A" }) )
    .append( $("<option/>", { text: "AR" }) )
    .append( $("<option/>", { text: "NS" }) )
    .val( status )
    .appendTo(this);
    

    Note that the whole select element should be built before appending it to the DOM. This is much better for performance, since any interaction with the DOM is very expensive.

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