Question

I have the following situation:

vec1  <- c("A", "B", "D", "C", "E", "A", "C")
vec2 <- c("A", "B", "C", "D", "F")

First question: which one is duplicated ? – answer “A” and “C” for vec1, 0 for vec2

Second question: Identify which is vec1 but not in vec2, irrespective of order (answer “E”)

or vice versa (answer “F”)

which(vec1 !=vec2)
which(vec2 !=vec1)

[1] 3 4 5 7
Warning message:
In vec1 != vec2 :
  longer object length is not a multiple of shorter object length

which is not what I expected….

Answer 1

Elements in vec1 that are duplicated:

vec1[duplicated(vec1)]

[1] "A" "C"

Elements in vec1 that are not in vec2:

vec1[is.na(match(vec1,vec2))]

[1] "E"

And vice versa:

vec2[is.na(match(vec1,vec2))]

[1] "F"