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Home/ Questions/Q 7695101
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T21:28:18+00:00 2026-05-31T21:28:18+00:00

I have the following source code: Processmethod() { QDialog *ProcessMessage = new QDialog; Ui::DialogProcessMessage

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I have the following source code:

    Processmethod()
{

    QDialog *ProcessMessage = new QDialog;      
    Ui::DialogProcessMessage Dialog;            
    Dialog.setupUi(ProcessMessage);             
    ProcessMessage->setModal(true);
    ProcessMessage->setAttribute(Qt::WA_DeleteOnClose); 
    ProcessMessage->show();



    PROCESSES START                     
}

After I want to show the QDialog “ProcessMessage” there are three QProcess processes included in three different following methods. If I disable these methods with // the popup window appears just fine, but if I enable the methods, the processes run fine, but the popup window does not appear. Any ideas/solutions ? greetings

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  1. Editorial Team
    Editorial Team
    2026-05-31T21:28:19+00:00Added an answer on May 31, 2026 at 9:28 pm

    Your window do not show until Process method is not return because main application loop implemented in main function

    int main(int argc, char *argv[])
    {
            QApplication a(argc, argv);
            QDialog w; // or other window
            w.show();
            return a.exec(); // main app loop (all drawing procedures called from here
    }
    

    So if you call your PROCESSES START nothing happened until Process method returns in QApplication::exec()

    You can start your processes in separate thread and send progress notification to you dialog by implementing signals\slots in queued mode

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