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Home/ Questions/Q 6886861
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T05:48:46+00:00 2026-05-27T05:48:46+00:00

I have the following source code. testObj = {} function testFun() { this.name =

  • 0

I have the following source code.

testObj = {}

function testFun()
{
    this.name = "hi";   
}

function test () {

    var instanceOfTestFun = new testFun();

    testObj.pointerToFun = instanceOfTestFun;

    instanceOfTestFun = null;

    console.log(testObj);

}

$(document).ready(test);

I expected to see ‘null’ for the console output of testObj, but I see testFun function. I thought javascript uses ‘pass by ref’ for objects.

Please…advise me…

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  1. Editorial Team
    Editorial Team
    2026-05-27T05:48:47+00:00Added an answer on May 27, 2026 at 5:48 am

    testObj.pointerToFun and instanceOfTestFun are two references to the same object.

    When you write instanceOfTestFun = null, you’re changing instanceOfTestFun to point to nothing.
    This does not affect testObj.pointerToFun, which still refers to the original object.

    If you change the original object (eg, instanceOfTestFun.name = "bye"), you will see the change through both accessors, since they both point to the (now-changed) object.

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