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Home/ Questions/Q 6703765
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T07:12:35+00:00 2026-05-26T07:12:35+00:00

I have the following sql 2008 table. ID RefundId RefundStatusId CreatedOn 334 549 3

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I have the following sql 2008 table.

ID  RefundId    RefundStatusId          CreatedOn
334 549         3                   2011-10-12 12:04:37.773
333 549         1                   2011-10-12 12:04:20.390
332 549         6                   2011-10-12 12:03:05.990

Any query can give me a result like:

RefundCheckId   StatusId             PreviousStatusId           CreatedOn
    549             3                    1                        2011-10-12 12:04:37.773
    549             1                    6                        2011-10-12 12:04:20.390
    549             6                    null                     2011-10-12 12:03:05.990

Solution below : Updated based on Marco’s answer.

SELECT t.RefundId AS RefundCheckId, t.RefundStatusId AS StatusId,
  (SELECT TOP 1 RefundStatusId FROM table
   WHERE RefundId = t.RefundId AND CreatedOn < t.CreatedOn
   ORDER BY CreatedOn DESC) AS PreviousStatusId, t.CreatedOn
FROM table t
WHERE t.RefundId = 549
ORDER BY t.CreatedOn DESC
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T07:12:36+00:00Added an answer on May 26, 2026 at 7:12 am

    Try

    MySql version

    SELECT t.RefundId AS RefundCheckId, t.RefundStatusId AS StatusId,
      (SELECT RefundStatusId FROM your_table 
       WHERE ID < t.ID
       ORDER BY ID DESC
       LIMIT 1) AS PreviousStatusId, t.CreatedOn
    FROM your_table t
    ORDER BY t.ID DESC
    

    MS-SQL version

    SELECT t.RefundId AS RefundCheckId, t.RefundStatusId AS StatusId,
      (SELECT TOP 1 RefundStatusId FROM your_table 
       WHERE ID < t.ID
       ORDER BY ID DESC) AS PreviousStatusId, t.CreatedOn
    FROM your_table t
    ORDER BY t.ID DESC
    
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