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Asked: May 11, 20262026-05-11T15:30:11+00:00 2026-05-11T15:30:11+00:00

I have the following sql (a simplification of the real problem): SELECT * FROM

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I have the following sql (a simplification of the real problem):

SELECT * FROM t WHERE myname LIKE '%{$input}%'; 

How do I escape the $input?
I can’t use the quoteInto (unless I miss something).
As

$sql=$DB->quoteInto('SELECT *                      FROM t                      WHERE myname LIKE '%?%'',$input); 

Will give me

SELECT * FROM t WHERE myname LIKE '%'my input'%'; 

and

$sql=$DB->quoteInto('SELECT *                      FROM t                      WHERE myname LIKE ?','%'.$input.'%'); 

Will give me something on the lines:

SELECT * FROM t WHERE myname LIKE '\%my input\%'; 
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  1. 2026-05-11T15:30:12+00:00Added an answer on May 11, 2026 at 3:30 pm

    The last option is works out well for me i’ve not experienced it escaping ‘%’. So $db->quote('%'.$_GET['query'].'%') outputs %queryvalue%

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