Question

I have the following sql statement:

SELECT
 COUNT(table2.programName),
 table2.programName
FROM
 table1
LEFT JOIN
 table2
ON
 table1.programID = table2.programID
WHERE
 table1.MemberID = 12345
AND
 table2.programName = (table2.programName associated with dynamic table2.programID)

I do realize the last AND statement is currently invalid but it is what I cannot seem to get my head around. While I can execute the query successfully by inserting a known value, the query needs to be generated dynamically (done with php) and the value will appear as a variable. I only put in parenthesis to show what I am trying to accomplish.

Any ideas how would I go about finding the programName associated with the programID in the parenthesis in a single sql statement?

EDIT – POSSIBLE ANSWER

So in testing out some more, I think I may have found the answer but am unsure if it is ‘good’ practice. Here is my code:

SELECT
    COUNT(table2.programName),
    table2.programName
FROM
    table1
LEFT JOIN
    table2
ON
    table1.programID = table2.programID
WHERE
    table1.MemberID = 12345
AND
    table2.programName = (SELECT table2.programName FROM table2 WHERE table2.programID = $id);

Answer 1

Use:

   SELECT t2.programname,
          COUNT(t2.programname)
     FROM TABLE2 t2
LEFT JOIN TABLE1 t1 ON t1.programid = t2.programid
                   AND t1.memberid = 12345
    WHERE t2.programid = $id
 GROUP BY t2.programname