Question

I have the following sql statement, which works perfect and since I’m transferring everything to PDO, I’ve having the worst time trying to convert this complicated statement. Here it is working below:

$sql_res=mysql_query("SELECT a.first_name, a.last_name, a.uid, a.hometown, 
IF(b.friend_two IS NULL, 0, 1) AS isFriend FROM users a LEFT JOIN friends 
b ON a.uid = b.friend_two AND b.friend_one = $uid WHERE  
CONCAT(a.first_name, ' ', a.last_name) LIKE '%$q%' AND a.uid <> $uid 
ORDER BY isFriend DESC");

I’ve been trying for hours to convert and this is all I could get from another S.O example (it’s not even close to working)

Any help is wonderfully appreciate. Oh and also $q is a POST variable from the user so PDO is a must in my case.

UPDATED Code (2nd time):

$sql = "select a.first_name, a.last_name, a.uid, a.hometown, 
IF(b.friend_two IS NULL, 0, 1) AS isFriend FROM users a LEFT JOIN 
friends b ON a.uid = b.friend_two AND b.friend_one = :friend_one 
where ( first_name like concat('%', :fname, '%') or last_name like 
concat('%', :lname, '%') ) and a.uid <> :uid ORDER BY isFriend DESC"; 
$stmt= $db->prepare($sql); $stmt->bindValue(':fname', "%$q%", PDO::PARAM_STR); 
$stmt->bindValue(':lname', "%$q%", PDO::PARAM_STR); 
$stmt->execute(array(':friend_one' => $uid,':uid' => $uid));

This works without any error but fails to produce the same results as the original sql statement.

Answer 1

removed the extra from and put () around your name filter, as
A OR B AND C = A OR (B AND C), and i gues you wanted (A OR) B AND C

select
  a.first_name,
  a.last_name,
  a.uid,
  a.hometown,
  IF(b.friend_two IS NULL, 0, 1) AS isFriend 
FROM users a 
LEFT JOIN friends b
  ON a.uid = b.friend_two AND b.friend_one = :uid
where 
  (
    first_name like concat('%', :fname, '%') or 
    last_name  like concat('%', :lname, '%') 
  ) and
  a.uid <> :uid 
ORDER BY
  isFriend DESC