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Editorial Team
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Asked: 2026-05-25T05:51:51+00:00

I have the following string and I would like to extract the elements (xx=yy)

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I have the following string and I would like to extract the elements (xx=”yy”) and what’s between the brackets. Here’s an example:

this too please

I’ve tried the following code but I’m quite a noob with regex. 

re.sub(r'\(.*)\[\/caption\]', "tokens: %1 %2 %3 %4 %5", self.content, re.IGNORECASE)

Thanks a lot in advance!

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1 Answer

  1. Editorial Team

    It’s probably not working for you because .* is greedy. Try [^"]* in its place. [^"] means the set of all characters except the quote character. Also, as you’ve pointed out in the comments, the token syntax, is \\n, not %n. Try this:

    re.sub(r'\*)" align="([^"]*)" width="([^"]*)" caption="([^"]*)"\](.*)\[\/caption\]', "tokens: \\1 \\2 \\3 \\4 \\5", self.content, re.IGNORECASE)

    Do the contents of the caption tag span multiple lines? If they do .* won’t capture the newlines. You’ll need to us something like [^\x00]* instead. [^\x00] means the set of all charchters except the null character.

    re.sub(r'\*)" align="([^"]*)" width="([^"]*)" caption="([^"]*)"\]([^\x00]*)\[\/caption\]', "tokens: \\1 \\2 \\3 \\4 \\5", self.content, re.IGNORECASE)

    On the off chance that your strings can actually legitimately contain null characters, you would need to use the re.DOTALL flag instead.

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