Question

I have the following string example:

PASSWORD = dsl3£$Roid
dfdfdf
fgdgfdfg
fgdfgdfg
dfgdfg
dfgdfgdfg

its stored in MySql Text field.

I need to get the “password” ie dsl3£$Roid

Its preceded by PASSWORD =
and there is a \n line break after. I can use nl2br to make the string like this:

PASSWORD = dsl3£$Roid<br>
dfdfdf<br>
fgdgfdfg<br>
fgdfgdfg<br>
dfgdfg<br>
dfgdfgdfg<br>

Been fighting with preg_match all day but no luck… Currently have 10k + rows, each with unique passwords and need some code to pull just the password.

Many thanks for help!

Answer 1

Not that hard.

/PASSWORD\s=\s(?P<PASSWORD>[^\n]+)?\n/msU

the match will contain ‘PASSWORD’ if it’s found in the text:

$text = YOUR_BLOB_HERE;

$match = array();
$count = preg_match('/PASSWORD\s=\s(?P<PASSWORD>[^\n]+)?\n/msU', $text, $match);

print_r($match);

/*  output:

Array
(
    [0] => PASSWORD = dsl3£$Roid

    [PASSWORD] => dsl3£$Roid
    [1] => dsl3£$Roid
)

*/