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Home/ Questions/Q 3316694
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T22:29:59+00:00 2026-05-17T22:29:59+00:00

I have the following string: $foo = ‘fdsfdsf’, ‘fsdfdsfdsfdsfds fdsf sdfd f sfs’, ‘fsdfsdfsd

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I have the following string:

$foo = "'fdsfdsf', 'fsdfdsfdsfdsfds fdsf sdfd f sfs', 'fsdfsdfsd f' fdfsdfdsfdsfsf";

I want to get everything between ' ' but from first to last occurrence.

I have tried to search my string by /.*('.*').*/ but only 'fdsfdsf' was taken, how to turn on greedy or something like that?

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  1. Editorial Team
    Editorial Team
    2026-05-17T22:30:00+00:00Added an answer on May 17, 2026 at 10:30 pm

    Try

    @result = $subject =~ m/'([^']*)'/g;
    

    This will give you the strings enclosed in single quotes within each field in the string.

    Of course, the quotes need to be balanced, and the regex match will be thrown off by escaped quotes in your string, so if those may occur, the pattern needs to be modified.

    For example,

    m/'((?:\\.|[^'])*)'/
    

    would work if quotes can be escaped with backlashes.

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