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Home/ Questions/Q 7693063
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T20:59:50+00:00 2026-05-31T20:59:50+00:00

I have the following string s = ~ VERSION 11 11 11.1 222 22

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I have the following string s = “~ VERSION 11 11 11.1 222 22 22.222”

I Want to extract the following into the following variables:

string Variable1 = "11 11 11.1"
string Variable2 = "222 22 22.222"

How do I extract this with regular expression? Or is there a better alternative way? (note, There may be variable spacing in between the the tokens I want to extract and the leading character may be something other than a ~, but it will definitely be a symbol:

e.g. could be:

~   VERSION   11 11 11.1  222 22 22.222
$   VERSION 11 11 11.1      222 22 22.222
@      VERSION    11 11 11.1          222 22 22.222

If regular expression does not make sense for this or if there is a better way, please recommend.
How do I preform the extraction into those two variables in python?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T20:59:51+00:00Added an answer on May 31, 2026 at 8:59 pm

    Try this:

    import re
    
    test_lines = """
    ~   VERSION   11 11 11.1  222 22 22.222
    $   VERSION 11 11 11.1      222 22 22.222
    @      VERSION    11 11 11.1          222 22 22.222
    """
    
    version_pattern = re.compile(r"""
    [~!@#$%^&*()]               # Starting symbol
    \s+                         # Some amount of whitespace
    VERSION                     # the specific word "VERSION"
    \s+                         # Some amount of whitespace
    (\d+\s+\d+\s+\d+\.\d+)      # First capture group
    \s+                         # Some amount of whitespace
    (\d+\s+\d+\s+\d+\.\d+)      # Second capture group
    """, re.VERBOSE)
    
    lines = test_lines.split('\n')
    
    for line in lines:
        m = re.match(version_pattern, line)
        if (m):
            print (line)
            print (m.groups())
    

    which gives output:

    ~   VERSION   11 11 11.1  222 22 22.222
    ('11 11 11.1', '222 22 22.222')
    $   VERSION 11 11 11.1      222 22 22.222
    ('11 11 11.1', '222 22 22.222')
    @      VERSION    11 11 11.1          222 22 22.222
    ('11 11 11.1', '222 22 22.222')
    

    Note the use of verbose regular expressions with comments.

    To convert the extracted version numbers to their numeric representation (i.e. int, float) use the regexp in @Preet Kukreti’s answer and convert using int() or float() as suggested.

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