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Home/ Questions/Q 6244551
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T12:20:45+00:00 2026-05-24T12:20:45+00:00

I have the following String: Something:string(lower-case) anything Somethingb:numbers I am trying to get the

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I have the following String:

“Something:string(lower-case) anything Somethingb:numbers”

I am trying to get the char after Something and the numbers after Somethingb with preg_replace.

Also, sometimes the string will be just the first part:

“Something char anything”

So what I need is an outcome like this using preg_replace:

“string(lowercase) , numbers”

or just

“string(lowercase)”

if the Something b is not in the string.

Any idea would be much appreciated.

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-24T12:20:46+00:00Added an answer on May 24, 2026 at 12:20 pm

    Here is regex for first case:

    /Something:([a-z]+).*?Somethingb:(\d+)/
    

    and replace

    $1 , $2
    

    also you can pass &$count parameter to know if replace was successful

    In second case do you want “Something char anything” to become “something char anything”? if this is so that you can just do strtolower($string) if $count == 0

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