Question

I have the following string ./test
and I want to replace it with test
so, I wrote the following in perl:
my $t =~ s/^.//;
however, that replaces ./test with /test
can anyone please suggest how I fix it so I get rid of the / too. thanks!

Answer 1

my $t =~ s/^\.\///;

You need to escape the dot and the slash.

The substitution is s/match/replace/. If you erase, it’s s/match//. You want to match “starts with a dot and a slash”, and that’s ^\.\/.