Question

I have the following string that I’m trying to parse into a dict of k,v

foo = “abc=foo.bazz; defg=6cab; rando=random; token=foobar”

I can achieve this with some really ugly code

foo_dict = {}
bar = foo.split(';') 
for item in bar:
  x = item.split('=')
foo_dict[x[0]] = x[1]

I’d much prefer this be a simple 1 line list comprehension.

Answer 1

What about using urlparse module:

In [1] import urlparse
In [2] foo = "abc=foo.bazz; defg=6cab; rando=random; token=foobar"
In [3]: urlparse.parse_qs('abc=foo.bazz; defg=6cab; rando=random; token=foobar')
Out[3]: 
     {' defg': ['6cab'],
      ' rando': ['random'],
      ' token': ['foobar'],
      'abc': ['foo.bazz']}

In [4]: dict(urlparse.parse_qsl('abc=foo.bazz; defg=6cab; rando=random; token=foobar'))
Out[4]: {' defg': '6cab', ' rando': 'random', ' token': 'foobar', 'abc': 'foo.bazz'}

Not sure if you wanted those blank values in keys or not, but obviously easy to clean.