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Home/ Questions/Q 7595657
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T21:43:32+00:00 2026-05-30T21:43:32+00:00

I have the following structure below. Using jQuery I need to take each link

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I have the following structure below. Using jQuery I need to take each link and display the href below it. I can use some child selectors to write code for each but I simply want to write something that does it for all div’s with the ‘col’ class, and will allow for future additions…

<div class="col">
    <a href="http://google.com">Google</a>
</div>

<div class="col">
    <a href="http://yahoo.com">Yahoo!</a>
</div>

<div class="col">
    <a href="http://facebook.com">Facebook</a>
</div>

<div class="col">
    <a href="http://twitter.com">Twitter</a>
</div>

The above should turn into…

<div class="col">
    <a href="http://google.com">Google</a>
    <span>http://google.com</span>
</div>

<div class="col">
    <a href="http://yahoo.com">Yahoo!</a>
    <span>http://yahoo.com</span>
</div>

<div class="col">
    <a href="http://facebook.com">Facebook</a>
    <span>http://facebook.com</span>
</div>

<div class="col">
    <a href="http://twitter.com">Twitter</a>
    <span>http://twitter.com</span>
</div>

Any help is appreciated!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T21:43:33+00:00Added an answer on May 30, 2026 at 9:43 pm

    This smacks of you not having tried to write the code at all. You should really be able to do this on your own.

    $('.col a').each(function() {
        var $this = $(this);
        $("<span>"+$this.attr('href')+"</span>").insertAfter($this);
    });
    
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