I have the following structure:
common-module
- Contains the common module related , services and persistence api
- Contains a common persistence context test-common-persistence-context.xml.
search-module (depends on Common Module)
- Contains the search module related model beans(marked with JPA Entity annotations), services and persistence api
- Contains search module related spring context files
booking-module (depends on Common Module)
– Contains the booking module related model beans(marked with JPA Entity annotations), services and persistence api
– Contains booking module related spring context files
In the common-module I have test-common-persistence-context.xml.For the sessionFactory bean having type
org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean I need to set the property “packagesToScan” value to the packages in which JPA Entity annotation marked model beans are present.Without it, I get the exception Unknown entity: MY_ENTITY_NAME
Common Module: test-common-persistence-context.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<!-- Property Place Holder -->
<context:property-placeholder location="classpath:test-common-persistence-bundle.properties" />
<!-- Data Source -->
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="${test.db.driverClassName}"/>
<property name="url" value="${test.db.jdbc.url}"/>
<property name="username" value="${test.db.username}"/>
<property name="password" value="${test.db.password}"/>
</bean>
<!--
Hibernate Configuration
-->
<bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean" >
<property name="dataSource" ref="dataSource"/>
<property name="packagesToScan" value="${test.packages.to.scan.jpa.annotations}"/>
<property name="hibernateProperties">
<value>
<!-- SQL dialect -->
hibernate.dialect=org.hibernate.dialect.PostgreSQLDialect
hibernate.hbm2ddl.auto=update
</value>
</property>
</bean>
<!-- Transaction Manager -->
<bean id="txManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory"/>
</bean>
<tx:annotation-driven transaction-manager="txManager"/>
</beans>
In my common-module there are no JPA entities so I don’t have any package to scan so I keep the “packagesToScan” property value empty
However I need to use the same persistence context in my search-module and booking-module tests (SearchPersistenceTestBase.java) so that the JPA entities in the respective module gets detected.
Search Module: SearchPersistenceTestBase.java
@Ignore
@ContextConfiguration(locations = {
"classpath:test-common-persistence-context.xml",
"classpath:test-search-spring-context.xml"})
@TransactionConfiguration(transactionManager="txManager", defaultRollback=true)
public class SearchPersistenceTestBase extends AbstractTransactionalJUnit4SpringContextTests {
}
Can anybody please guide me in how to achieve this desired behavior with the set up I have shown above?
** Approach I tried **
I thought of using an additional java.lang.String type bean whose value is set from a properties file
<bean id="entityPackagesToScan" class="java.lang.String">
<constructor-arg value="${test.packages.to.scan.jpa.annotations}" />
</bean>
where test.packages.to.scan.jpa.annotations is defined as empty in test-common-persistence-bundle.properties
And then I override the bean definition in test-search-spring-context.xml
test-search-spring-context.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<!-- Property Place Holder -->
<context:property-placeholder location="classpath:test-search-bundle.properties" />
.. context-component scan elements here
<bean id="entityPackagesToScan" class="java.lang.String">
<constructor-arg value="${test.packages.to.scan.jpa.annotations}" />
</bean>
</beans>
where test.packages.to.scan.jpa.annotations is defined as “com.search.model” in test-search-bundle.properties
But this didn’t worked and I got the exception Unknown entity: MY_ENTITY_NAME
Thanks,
Jignesh
Ok I got this resolved. org.springframework.beans.factory.config.PropertyOverrideConfigurer is what was needed.I am posting here the solution for reference in case anybody faces similar problem like I mentioned in first post:
Common Module: test-common-persistence-context.xml
Search Module: test-search-spring-context.xml
Search module: test-search-bundle.properties
Thanks,
Jignesh