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Home/ Questions/Q 7880017
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T04:02:36+00:00 2026-06-03T04:02:36+00:00

I have the following table: id | roomid | courseid | day(NUM) | start(TIME)

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I have the following table:

id | roomid | courseid | day(NUM) | start(TIME) | end(TIME)

This is one part of larget query that I am stuck with. How can I show all id’s that have NO time break in between courses in specific rooms on specific day? Kind of stuck here.
I guess I have to use ‘ADDTIME()’ function to to find out the difference in course1 end time and course 2start time => that have 0. I have been looking at it for quite some time now and I am stuck!

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  1. Editorial Team
    Editorial Team
    2026-06-03T04:02:38+00:00Added an answer on June 3, 2026 at 4:02 am

    If all you are interested in is full utilisation.
    If a day is say 7 hours, (9-5 – 1 hour lunch break), call it 420 minutes to make things easy.
    Then 420 – Sum(MINUTE(TIMEDIFF(t2,t1)) = 0 would mean the room was fully booked up.

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