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Home/ Questions/Q 6928637
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T11:12:54+00:00 2026-05-27T11:12:54+00:00

I have the following table mysql> desc items; +——————-+————–+——+—–+———+—————-+ | Field | Type |

  • 0

I have the following table

mysql> desc items;
+-------------------+--------------+------+-----+---------+----------------+
| Field             | Type         | Null | Key | Default | Extra          |
+-------------------+--------------+------+-----+---------+----------------+
| id                | int(11)      | NO   | PRI | NULL    | auto_increment |
| code              | varchar(255) | YES  |     | NULL    |                |
| name              | varchar(255) | YES  |     | NULL    |                |
| price             | float        | YES  |     | NULL    |                |
| ingredient_id     | int(11)      | YES  |     | NULL    |                |
| ingredient_id2    | int(11)      | YES  |     | 0       |                |
| ingredient_id3    | int(11)      | YES  |     | 0       |                |
+-------------------+--------------+------+-----+---------+----------------+

and my ingredients table

mysql> desc ingredients;
+--------------+--------------+------+-----+---------+----------------+
| Field        | Type         | Null | Key | Default | Extra          |
+--------------+--------------+------+-----+---------+----------------+
| id           | int(11)      | NO   | PRI | NULL    | auto_increment |
| name         | varchar(255) | YES  |     | NULL    |                |
+--------------+--------------+------+-----+---------+----------------+

and ingredient_id, ingredient_id2, ingredient_id3 columns are foreign keys of ‘ingredients’ table, my requirement is to create a select query to display items and ingredients as follows

select id, code, name, price, name as ingredient_name1, name as ingredient_name2, name as ingredient_name3

But I dont know how to join the same table 3 times, can someone help me to understand this join condition

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  1. Editorial Team
    Editorial Team
    2026-05-27T11:12:55+00:00Added an answer on May 27, 2026 at 11:12 am

    TRY

    SELECT i.id, i.name, i.code, i.price, 
           ig1.name AS igName1,ig2.name AS igName2,ig3.name as igName3
    FROM items i 
    INNER JOIN ingredients ig1 ON ig1.id=i.ingredient_id
    INNER JOIN ingredients ig2 ON ig2.id=i.ingredient_id2
    INNER JOIN ingredients ig3 ON ig3.id=i.ingredient_id3
    
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