Question

I have the following table with data:

tag    dt          value 1      2009/03/01  10.2 2      2009/03/01  12 3      2009/03/01  120 .... 1      2009/03/02  13.2 2      2009/03/02  9 3      2009/03/02  23 .... 

Basically, for a group of tags, there are values along date (March 1, 2, …). I would like to have data in a different view like this:

dt             tag(1)   tag(2)   tag(3) 2009/03/01     10.2     12       120 2009/03/02     13.2     9        23 .... 

I tried to use the following SQL to get only tag(1)’ value

SELECT dt, SUM(value) [tag(1)] FROM myTable GROUP BY dt, tagid HAVING tagid = 1 

how can I get all tag(1), tag(2) and tag(3)’s values in one column by date by using TSQL?

By the way I have Microsoft SQL Server 2005.

Answer 1

SELECT dt,  SUM(case when tag=1 then value else 0 end) as tag1, SUM(case when tag=2 then value else 0 end) as tag2, SUM(case when tag=3 then value else 0 end) as tag3 FROM myTable GROUP BY dt