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Home/ Questions/Q 237381
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T20:25:15+00:00 2026-05-11T20:25:15+00:00

I have the following template String: Hello [Name] Please find attached [Invoice Number] which

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I have the following template String: "Hello [Name] Please find attached [Invoice Number] which is due on [Due Date]".

I also have String variables for name, invoice number and due date – what’s the best way to replace the tokens in the template with the variables?

(Note that if a variable happens to contain a token it should NOT be replaced).


EDIT

With thanks to @laginimaineb and @alan-moore, here’s my solution:

public static String replaceTokens(String text, 
                                   Map<String, String> replacements) {
    Pattern pattern = Pattern.compile("\\[(.+?)\\]");
    Matcher matcher = pattern.matcher(text);
    StringBuffer buffer = new StringBuffer();

    while (matcher.find()) {
        String replacement = replacements.get(matcher.group(1));
        if (replacement != null) {
            // matcher.appendReplacement(buffer, replacement);
            // see comment 
            matcher.appendReplacement(buffer, "");
            buffer.append(replacement);
        }
    }
    matcher.appendTail(buffer);
    return buffer.toString();
}
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  1. Editorial Team
    Editorial Team
    2026-05-11T20:25:15+00:00Added an answer on May 11, 2026 at 8:25 pm

    The most efficient way would be using a matcher to continually find the expressions and replace them, then append the text to a string builder:

    Pattern pattern = Pattern.compile("\\[(.+?)\\]");
    Matcher matcher = pattern.matcher(text);
    HashMap<String,String> replacements = new HashMap<String,String>();
    //populate the replacements map ...
    StringBuilder builder = new StringBuilder();
    int i = 0;
    while (matcher.find()) {
        String replacement = replacements.get(matcher.group(1));
        builder.append(text.substring(i, matcher.start()));
        if (replacement == null)
            builder.append(matcher.group(0));
        else
            builder.append(replacement);
        i = matcher.end();
    }
    builder.append(text.substring(i, text.length()));
    return builder.toString();
    
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