Question

I have the following text pattern,

os2v some text openssl-56 test Is Not founded

and need to extract the word before "test Is Not founded", i.e., in this case: openssl-56

Currently I’ve tried to use this regular expression:

if (m/os2v (\s+) test is NOT founded/i){
    print $1
}

But why does the code not enter the if statement?

Answer 1

The obvious problems are that your text doesn’t include the word “Update” and \s will match whitespace.