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Home/ Questions/Q 6592715
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T17:35:24+00:00 2026-05-25T17:35:24+00:00

I have the following three SQL queries. I would like to combine them into

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I have the following three SQL queries. I would like to combine them into one is possible, either using the current method, or another method if it would be more efficient.

NOTE: I need to know the distinct count values for all three WHERE clauses.

Query 1:

SElECT COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images
) AS union_table
WHERE primaryId = $imgId AND imgWidth = $maxImageWidth AND imgHeight = $maxImageHeight;

QUERY 2:

SElECT COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images
) AS union_table
WHERE primaryId = $imgId AND imgWidth = $maxImageWidth AND imgHeight != $maxImageHeight;

QUERY 3:

SElECT COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images
) AS union_table
WHERE primaryId = $imgId AND imgWidth != $maxImageWidth AND imgHeight = $maxImageHeight;

Also, my database is MySQL. I have heard that using != for “not equal” doesn’t work in all cases, but that <> is better. In my case, should != be fine?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T17:35:25+00:00Added an answer on May 25, 2026 at 5:35 pm

    This might work for you.

    SElECT COUNT(*) AS imgCount FROM (
        SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images
        UNION ALL 
        SELECT imgHeight, imgWidth, primaryId FROM secondary_images
    ) AS union_table
    WHERE primaryId = $imgId 
    AND (imgWidth != $maxImageWidth AND imgHeight = $maxImageHeight
    OR imgWidth = $maxImageWidth AND imgHeight != $maxImageHeight
    OR imgWidth = $maxImageWidth AND imgHeight = $maxImageHeight);
    

    I also believe this is equivalent, although I’m not sure.

    SElECT COUNT(*) AS imgCount FROM (
        SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images
        UNION ALL 
        SELECT imgHeight, imgWidth, primaryId FROM secondary_images
    ) AS union_table
    WHERE primaryId = $imgId 
    AND (imgWidth = $maxImageWidth OR imgHeight = $maxImageHeight);
    

    As per the request, here is a single query that returns 3 rows.

    SELECT 'ALL EQUAL' AS COL1,COUNT(*) AS imgCount FROM (
        SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images
        UNION ALL 
        SELECT imgHeight, imgWidth, primaryId FROM secondary_images
    ) AS union_table
    WHERE primaryId = $imgId AND imgWidth = $maxImageWidth AND imgHeight = $maxImageHeight
    UNION ALL
    SELECT 'WIDTH EQUAL' AS COL1,COUNT(*) AS imgCount FROM (
        SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images
        UNION ALL 
        SELECT imgHeight, imgWidth, primaryId FROM secondary_images
    ) AS union_table
    WHERE primaryId = $imgId AND imgWidth = $maxImageWidth AND imgHeight != $maxImageHeight;
    UNION ALL
    SELECT 'HEIGHT EQUAL' AS COL1,COUNT(*) AS imgCount FROM (
        SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images  
        UNION ALL 
        SELECT imgHeight, imgWidth, primaryId FROM secondary_images
    ) AS union_table
    WHERE primaryId = $imgId AND imgWidth != $maxImageWidth AND imgHeight = $maxImageHeight;
    
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