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Home/ Questions/Q 7899027
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T08:35:44+00:00 2026-06-03T08:35:44+00:00

I have the following two functions defined in my .bash_functions (which gets sourced into

  • 0

I have the following two functions defined in my .bash_functions (which gets sourced into .bashrc):

up() {
  if (($# == 0)); then
    cd ..
  else
    for basename; do
      local result=$(_foo)
      echo $result
      cd $result
    done
  fi
}

_foo() {
  echo ${PWD%/$1/*}/$basename
}

While I can execute _foo, when i execute up, up doesn’t seem to know _foo. Am I doing something wrong here, or is this just not possible?

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  1. Editorial Team
    Editorial Team
    2026-06-03T08:35:45+00:00Added an answer on June 3, 2026 at 8:35 am

    It does “know” _foo, but you don’t pass a parameter to _foo, so probably that’s causing the confusion.

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