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Home/ Questions/Q 6162523
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T21:40:09+00:00 2026-05-23T21:40:09+00:00

I have the following two routines in Flash Builder: public function getData():void { httpService

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I have the following two routines in Flash Builder:

public function getData():void {

    httpService = new HTTPService();
    httpService.url = "https://mongolab.com/api/1/databases/xxx/collections/system.users/?apiKey=xxx";
    httpService.resultFormat = HTTPService.RESULT_FORMAT_TEXT;
    httpService.addEventListener(ResultEvent.RESULT, resultHandler);
    httpService.send();
}

public function resultHandler(event:ResultEvent):void {

    var rawData:String = String(event.result);
    var arr:Array = JSON.decode(rawData) as Array;
    Debug.log(rawData);
    Debug.log(arr);

    httpService.removeEventListener(ResultEvent.RESULT, resultHandler);
}

rawData is displayed as JSON data but arr is displayed as [object Object] rather than an array.

What am I doing wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T21:40:09+00:00Added an answer on May 23, 2026 at 9:40 pm

    this

    var jsonStr:String = '{"glossary": {"title": "example glossary","GlossDiv": {"title": "S"},"GlossSee": "markup"}}';
    

    will be parsed and JSON.decode returns an Object and you can access the attributes like this:

    var obj:* = JSON.decode(jsonStr);
    trace(obj.glossary);
    

    this

    var jsonStr:String = '[{"title":"asd"},{"title":"asd"},{"title":"asd"},{"title":"asd"}]';
    

    will be parsed and returns an Array (which if you trace it, will return [object Object]).

    so if you don’t know what data is returned you could just check if

    var result:* = JSON.decode(jsonStr);
    if (result.length != undefined) {
      // array
      var arr:Array = result as Array;
    }
    else {
      // object
      var obj:Object = result as Object;
    }
    

    a try/catch around decode would also be good, because you don’t know if the jsonStr is well-formed…

    cheers

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