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Home/ Questions/Q 7648663
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T10:46:30+00:00 2026-05-31T10:46:30+00:00

I have the following typedef function prototype: typedef void (*sa_sigaction_t)(int, siginfo_t *, void *);

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I have the following typedef function prototype:

typedef void (*sa_sigaction_t)(int, siginfo_t *, void *);

I have no idea how to use it. I understand that (int, siginfo_t *, void*) is typedef-ed into sa_sigaction_t. But how would I use it? These are all return types with no variable names specified.

So I assume I want to create a variable: sa_sigaction_t handler. How would I use it? The syntax is quite confusing.

Thanks,

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  1. Editorial Team
    Editorial Team
    2026-05-31T10:46:31+00:00Added an answer on May 31, 2026 at 10:46 am

    I understand that (int, siginfo_t , void) is typedef-ed into sa_sigaction_t.

    Actually no. sa_sigaction_t is a pointer to a function that returns void and takes (int, siginfo_t *, void *) as parameters.

    So if you have:

    void foo(int, siginfo_t*, void*)
    {
    }
    

    you can do:

    sa_sigaction_t fooPtr = &foo;
    

    and then call it like this:

    fooPtr(0,NULL,NULL);
    
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