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Home/ Questions/Q 6756991
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T13:35:34+00:00 2026-05-26T13:35:34+00:00

I have the following URL: http://sub.mysite.com/store/?store=Fine+Ting&storeid=3726&test1=value1&test2=value2 Using print_r(parse_url($url)) gives me this: Array ( [scheme]

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I have the following URL:
http://sub.mysite.com/store/?store=Fine+Ting&storeid=3726&test1=value1&test2=value2

Using print_r(parse_url($url)) gives me this:

Array ( 
  [scheme] => http 
  [host] => sub.mysite.com 
  [path] => /store/ 
  [query] => store=Fine+Ting& 
  [fragment] => 038;storeid=3726&test1=value1&test2=value2 
) 

According to the documentation I should only get fragment after the hashmark #.

Why then is parse_url returning fragment? Shouldn’t that be in [query]?

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  1. Editorial Team
    Editorial Team
    2026-05-26T13:35:35+00:00Added an answer on May 26, 2026 at 1:35 pm

    You have a problem with you url, the ampersand is encoded in htmlentities (&). Therefore parse_str thinks, the fragment is starting there.

    Try using html_entity_decode before passing the url to parse_url.

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