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Home/ Questions/Q 8798485
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T00:06:29+00:00 2026-06-14T00:06:29+00:00

I have the following URL: https://api-test.company.com/contacts?q=email= jlowder@company.com I am parsing it using: String URL

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I have the following URL:

https://api-test.company.com/contacts?q=email=“jlowder@company.com”

I am parsing it using:

String URL = "https://api-test.company.com/contacts?" + URLEncoder.encode("q=email=jlowder@company.com", "UTF-8");

I have also tried “ISO-8859-1”, but both return this for my URL:

https://api-test.homeaway.com/contacts?q%3Demail%3Djlowder%40homeaway.com

In order to receive the correct response from my server, I need the url to be:

https://api-test.company.com/contacts?q=email=%22jlowder@company.com%22

The %22 is the ” ” marks around the email address.

How do I go about forming the correct URL? None of the examples I can find do this..

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  1. Editorial Team
    Editorial Team
    2026-06-14T00:06:30+00:00Added an answer on June 14, 2026 at 12:06 am

    If you really want this, then you have to put the quotes also into the string:

    String URL = "https://api-test.company.com/contacts?q=email=" + URLEncoder.encode("\"jlowder@company.com\"", "UTF-8");
    

    gives:
    https://api-test.company.com/contacts?q=email=%22jlowder%40company.com%22

    btw.: You want to name that String url, not URL.

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