Question

I have the following XML:

<assessment>
    <section>
        <item>
            <attributes>
                <variables>
                    <variable>
                        <variable_name value="MORTIMER"/>
                    </variable>
                </variables>
            </attributes>
        </item>
        <item>
            <attributes>
                <variables>
                    <variable>
                        <variable_name value="FRED"/>
                    </variable>
                </variables>
            </attributes>
        </item>
        <item>
            <attributes>
                <variables>
                    <variable>
                        <variable_name value="MORTIMER"/>
                    </variable>
                </variables>
            </attributes>
        </item>
    </section>
</assessment>

I have the following XSLT to process that XML:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output method="text"/>

 <xsl:key name="kValueByVal" match="item//variables//variable_name" 
          use="@value"/>

 <xsl:template match="assessment">
     <xsl:for-each select="
      .//item//variables//variable_name/@value
      ">
        <xsl:value-of select=
        "concat(., ' ', count(key('kValueByVal', .)), '&#xA;')"/>
         <br/>
     </xsl:for-each>
 </xsl:template>
</xsl:stylesheet>

It outputs the following, which is almost what I want:

MORTIMER 2
FRED 1
MORTIMER 2

It lists each of the variable_names and how many times each occurs. The only problem is that it gives this count once for each time the variable_name occurs instead of only once.

This is what I want it to output:

MORTIMER 2
FRED 1

How do I modify the XSLT code to give me that? Note that we’re using XSLT 1.0.

The following solution, which seems like it should work, outputs nothing:

<xsl:stylesheet version="2.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output method="text"/>

 <xsl:key name="kValueByVal" match="item//variables//variable_name"
          use="@value"/>

 <xsl:template match="assessment">
     <xsl:for-each select=".//item//variables//variable_name/@value[generate-id()
                                                                    =
                                                                    generate-id(key('kValueByVal',.)[1])]">
        <xsl:value-of select=
        "concat(., ' ', count(key('kValueByVal', .)), '&#xA;')"/>
         <br/>
     </xsl:for-each>
 </xsl:template>
</xsl:stylesheet>

Answer 1

You really need to understand how the Muenchian grouping works, otherwise you’d be asking variations of the same questions forever.

Do read Jeni Tennison’s tutorial.

Here is a solution for your latest question:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output method="text"/>

 <xsl:key name="kVarNameByVal" match="variable_name"
          use="@value"/>

 <xsl:template match=
  "variable_name[generate-id()
                =
                 generate-id(key('kVarNameByVal', @value)[1])
                ]
  ">
        <xsl:value-of select=
        "concat(@value, ' ', count(key('kVarNameByVal', @value)), '&#xA;')"/>
         <br/>
 </xsl:template>
</xsl:stylesheet>

When this transformation is performed on the provided XML document, the wanted result is produced:

MORTIMER 2
FRED 1