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Home/ Questions/Q 8142755
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T12:54:35+00:00 2026-06-06T12:54:35+00:00

I have the following XML code. You will notice the tag Description is repeated,

  • 0

I have the following XML code.

You will notice the tag Description is repeated, but with different attributes.

I am using XSLT to try and remove the Description tag with the enabled attribute.

<Batch>
- <Promotion>
  <LastUpdated>2008-01-22T11:58:05+00:00</LastUpdated> 
  <MajorVersion>1</MajorVersion> 
  <MinorVersion>29</MinorVersion> 
  <PromotionID>000873</PromotionID> 
  <Description enabled="1">*P* Free Mistletoe</Description> 
  <Description country="GB" language="en" variant="">WANTED LINE 1</Description>
 </Promotion>
 <Promotion>
   <LastUpdated>2008-01-22T11:58:05+00:00</LastUpdated> 
   <MajorVersion>1</MajorVersion> 
   <MinorVersion>29</MinorVersion> 
   <PromotionID>000874</PromotionID> 
   <Description enabled="1">*P* Free Mistletoe</Description> 
   <Description country="GB" language="en" variant="">WANTED LINE 2</Description>
 </Promotion> 
</batch>

This is what I am trying to get to, there are other tags, it is the removal of one
line based on an attribute I am trying to resolve.

- <promotions>
-   <promotion>
      <promotionID>000873</promotionID> 
      <description country="GB" language="en" variant="">WANTED LINE 1</description>
    </promotion>
-   <promotion> 
      <promotionID>000874</promotionID> 
      <description country="GB" language="en" variant="">WANTED LINE 2</description>
    </promotion> 
  </promotions>

The XSLT code I am using is

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>

<xsl:template match="node()|@*">
  <xsl:copy>
  <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
</xsl:template>
<xsl:template match="//promotion/Description[@country='GB']"/> 
<xsl:template match="/"> 

<promotions> 
<xsl:for-each select="Batch/Promotion">  
  <promotion>
    <promotion_id><xsl:value-of select="PromotionID"/></promotion_id>    
    <description><xsl:value-of select="Description"/></description>
  </promotion>
</xsl:for-each>   
</promotions>   
</xsl:template>
</xsl:stylesheet> 

If anyone could point me in the right direction I would be very grateful.

Paul

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T12:54:36+00:00Added an answer on June 6, 2026 at 12:54 pm

    Generally, in order to remove an element, you have to specify a template without any contents. In your case, this could be:

    <xsl:template match="/Batch/Promotion/Description[@enabled = '1']"/>
    

    In your XSLT code, however, you have the somewhat special case of constructing your own <description> element. In order to get exactly the value of the desired <Description> element, select it in your <xsl:value-of> element:

    <description><xsl:value-of select="Description[@country = 'GB']"/></description>
    

    This is what you have described in your question, however your expected result code implies that you already want to copy the attributes of the <Description> element? In that case, I’d go for this solution with <xsl:copy-of>:

    <description><xsl:copy-of select="Description[@country = 'GB']/node()|Description[@country = 'GB']/@*"/></description>
    

    It copies the whole contents of the <Description> element (node()), as well as any of its attributes (@*).

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