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Home/ Questions/Q 7006975
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T21:32:47+00:00 2026-05-27T21:32:47+00:00

I have the following XML data. I have no control on the structure of

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I have the following XML data. I have no control on the structure of this data, this is how I’m receiving it.

<data>
  <row>
    <value name="CustomerID">1</value>
    <value name="CustomerName">Joe</value>
    <value name="Cost">22.50</value>
  </row>
  <row>
    <value name="CustomerID">1</value>
    <value name="CustomerName">Joe</value>
    <value name="Cost">55.50</value>
  </row>
  <row>
    <value name="CustomerID">2</value>
    <value name="CustomerName">Jane</value>
    <value name="Cost">10</value>
  </row>
  <row>
    <value name="CustomerID">2</value>
    <value name="CustomerName">Jane</value>
    <value name="Cost">13.50</value>
  </row>
    <row>
    <value name="CustomerID">3</value>
    <value name="CustomerName">Jim</value>
    <value name="Cost">50</value>
  </row>
</data>

I need to use XSLT v1.0 to display the data grouped by Customer ID and with a total for each customer. I’ve tried searching many articles but nothing has this kind of strange structure.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T21:32:48+00:00Added an answer on May 27, 2026 at 9:32 pm

    Use:

    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
        <xsl:output method="xml" indent="yes"/>
    
        <xsl:key name="k" match="row" use="value[@name = 'CustomerID']"/>
    
        <xsl:template match="data">
            <xsl:copy>
                <xsl:apply-templates select="row[generate-id(.) = generate-id(key('k', value[@name = 'CustomerID']))]"/>
            </xsl:copy>
        </xsl:template>
    
        <xsl:template match="row">
            <xsl:copy>
                <xsl:copy-of select="value[@name = 'CustomerID']"/>
                <xsl:copy-of select="value[@name = 'CustomerName']"/>
                <sum>
                    <xsl:value-of select="sum(key('k', value[@name = 'CustomerID'])/value[@name = 'Cost'])"/>
                </sum>
            </xsl:copy>
        </xsl:template>
    </xsl:stylesheet>
    

    Output:

    <data>
      <row>
        <value name="CustomerID">1</value>
        <value name="CustomerName">Joe</value>
        <sum>78</sum>
      </row>
      <row>
        <value name="CustomerID">2</value>
        <value name="CustomerName">Jane</value>
        <sum>23.5</sum>
      </row>
      <row>
        <value name="CustomerID">3</value>
        <value name="CustomerName">Jim</value>
        <sum>50</sum>
      </row>
    </data>
    
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