Question

I have the following xml file:

<?xml version='1.0' encoding='UTF-8' standalone='no' ?> <config>  <a>   <b>    <param>p1</param>     <param>p2</param>    </b>  </a> </config> 

and the xpath code to get my node params:

Document doc = ...; XPath xpath = XPathFactory.newInstance().newXPath(); XPathExpression expr = xpath.compile('/config/a/b'); Object o = expr.evaluate(doc, XPathConstants.NODESET); NodeList list = (NodeList) o; 

but it turns out that the nodes list (list) has 5 children, including '\t\n', instead of just two. Is there something wrong with my code? How can I just get my two nodes?

Thank you!

Answer 1

so the xpath looks like: /config/a/b/*/text(). And the output for :

for (int i = 0; i < nodes.getLength(); i++) {         System.out.println(nodes.item(i).getNodeValue());     } 

would be as expected: p1 and p2