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Home/ Questions/Q 8143555
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T13:08:59+00:00 2026-06-06T13:08:59+00:00

I have the following XML file:- <?xml version=1.0 encoding=UTF-8?> <viewentries> <viewentry position=1> <entrydata columnnumber=0>

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I have the following XML file:-

<?xml version="1.0" encoding="UTF-8"?>
<viewentries>
    <viewentry position="1">
        <entrydata columnnumber="0">
            <text>Text1</text>
        </entrydata>
        <entrydata columnnumber="1">
            <text>Text2</text>
        </entrydata>
        <entrydata columnnumber="2">
            <text>Text3</text>
        </entrydata>
    </viewentry>
    <viewentry position="2">
        <entrydata columnnumber="0">
            <text>Text1</text>
        </entrydata>
        <entrydata columnnumber="1">
            <text>Text2</text>
        </entrydata>
        <entrydata columnnumber="2">
            <text>Text3</text>
        </entrydata>
    </viewentry>
</viewentries>

I need to transform this XML file using an XSL stylesheet to the following:-

<?xml version="1.0" encoding="UTF-8"?>
<records>
    <record position="1" col0="Text1" col1="Text2" col2="Text3"/>
    <record position="2" col0="Text1" col1="Text2" col2="Text3"/>
</records>

I have no real idea where to start.

Each element needs to be converted to a element, pulling through the position attribute, however each needs to be made into the attribute name, and each child attribute needs to be made into the attribute value.

Any help is greatly appreciated.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T13:09:00+00:00Added an answer on June 6, 2026 at 1:09 pm

    This transformation:

    <xsl:stylesheet version="1.0"
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
     <xsl:output omit-xml-declaration="yes" indent="yes"/>
     <xsl:strip-space elements="*"/>
    
     <xsl:template match="/*">
      <records>
        <xsl:apply-templates/>
      </records>
     </xsl:template>
    
     <xsl:template match="viewentry">
      <record>
        <xsl:apply-templates/>
      </record>
     </xsl:template>
    
     <xsl:template match="entrydata">
      <xsl:attribute name="col{@columnnumber}">
        <xsl:value-of select="text"/>
      </xsl:attribute>
     </xsl:template>
    </xsl:stylesheet>
    

    when applied on the provided XML document:

    <viewentries>
        <viewentry position="1">
            <entrydata columnnumber="0">
                <text>Text1</text>
            </entrydata>
            <entrydata columnnumber="1">
                <text>Text2</text>
            </entrydata>
            <entrydata columnnumber="2">
                <text>Text3</text>
            </entrydata>
        </viewentry>
        <viewentry position="2">
            <entrydata columnnumber="0">
                <text>Text1</text>
            </entrydata>
            <entrydata columnnumber="1">
                <text>Text2</text>
            </entrydata>
            <entrydata columnnumber="2">
                <text>Text3</text>
            </entrydata>
        </viewentry>
    </viewentries>
    

    produces the wanted, correct result:

    <records>
       <record col0="Text1" col1="Text2" col2="Text3"/>
       <record col0="Text1" col1="Text2" col2="Text3"/>
    </records>
    

    Explanation:

    Proper use of templates, the xsl:attribute instruction and AVT.

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