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Home/ Questions/Q 9220111
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T03:16:20+00:00 2026-06-18T03:16:20+00:00

I have the full path name of a given folder for e.g. c:\foo\bar Now

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I have the full path name of a given folder for e.g.

c:\foo\bar

Now I would like to reference a file inside c:\foo named baz.txt,

c:\foo\bar\..\baz.txt

I am currently using the .. path operator to go down one level and get the file that I need.

Is there a function that can do path manipulations, for e.g. UpOneLevel(str) -> str ? I know I can write one by splitting the string and removing the last token, but I would rather it be a built-in / library function so I don’t get into trouble later if there are for e.g. escaped backslashes.

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  1. Editorial Team
    Editorial Team
    2026-06-18T03:16:21+00:00Added an answer on June 18, 2026 at 3:16 am

    Use the ExpandFileName function:

    var
      S: string;
    begin
      S := 'c:\foo\bar\..';
      S := ExpandFileName(S);
      ShowMessage(S);
    end;
    

    The message from the above example will show the c:\foo path.

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