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Home/ Questions/Q 678463
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T01:09:09+00:00 2026-05-14T01:09:09+00:00

i have the function: const A& f(…) {…} a. const A a1 = f(..);

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i have the function: const A& f(…) {…}

a. const A a1 = f(..);
b. const A &a2 = f(...);

which of the is the better one to use? in both cases, if i understand correctly, i prevent the possibility of modifying the returned object.
in the first option, the copy constructor of A will be called – am i correct?

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  1. Editorial Team
    Editorial Team
    2026-05-14T01:09:09+00:00Added an answer on May 14, 2026 at 1:09 am

    It depends on what you want.

    In the first case you create a new const object that is constructed from the returned reference. It will be a snapshot of what was returned and will be valid for its entire lifetime.

    In the second you just initialize a reference. This means that any changes to the original object will be visible through the reference but there is a danger that the referred object will be destroyed while the reference is still alive.

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