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Home/ Questions/Q 8568929
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T18:13:01+00:00 2026-06-11T18:13:01+00:00

I have the int cannot be dereferenced error in the below code where I

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I have the int cannot be dereferenced error in the below code where I have //error is here. I’m confused because the variable b is used to reference a spot in the empl array later in the line without showing as an error. So how do I fix this and why is it generating an error?
I would appreciate any help. Example code would be great too as that seems to be the way I learn best. Thanks!

public static void bubbleSort(Employee[] empl) {
    for (int a = 1; a < empl.length; a++) 
    {
        for (int b = 0; b < empl.length - a; b++) 
        {
            if (((empl[b].//error is here
                    getEmployeeNumber()).compareTo
                   ((empl[b + 1].getEmployeeNumber()))) > 0) 
            {
               // swap employees[b] with employees[b+1]
               Employee temp = empl[b];
               empl[b] = empl[b + 1];
               empl[b + 1] = temp;
            }
        }
    }
}

Edit: Any other suggestions for sorting the array by Employee Number are welcome.

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  1. Editorial Team
    Editorial Team
    2026-06-11T18:13:02+00:00Added an answer on June 11, 2026 at 6:13 pm

    getEmployeeNumber() apparently returns an int.

    int is a primitive type, not an object.
    Therefore, you cannot call methods like compareTo() on it.

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